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960=(8+2x)(x)
We move all terms to the left:
960-((8+2x)(x))=0
We add all the numbers together, and all the variables
-((2x+8)x)+960=0
We calculate terms in parentheses: -((2x+8)x), so:We get rid of parentheses
(2x+8)x
We multiply parentheses
2x^2+8x
Back to the equation:
-(2x^2+8x)
-2x^2-8x+960=0
a = -2; b = -8; c = +960;
Δ = b2-4ac
Δ = -82-4·(-2)·960
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7744}=88$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-88}{2*-2}=\frac{-80}{-4} =+20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+88}{2*-2}=\frac{96}{-4} =-24 $
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