1+3x+20=-3(x-7)

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Solution for 1+3x+20=-3(x-7) equation: 



1+3x+20=-3(x-7)

We move all terms to the left:

1+3x+20-(-3(x-7))=0

We add all the numbers together, and all the variables

3x-(-3(x-7))+21=0



We calculate terms in parentheses: -(-3(x-7)), so:

-3(x-7)

We multiply parentheses

-3x+21

Back to the equation:

-(-3x+21)



We get rid of parentheses

3x+3x-21+21=0

We add all the numbers together, and all the variables

6x=0

x=0/6

x=0

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