4n+2n=-7(n+2)-(6-3n)

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Solution for 4n+2n=-7(n+2)-(6-3n) equation: 



4n+2n=-7(n+2)-(6-3n)

We move all terms to the left:

4n+2n-(-7(n+2)-(6-3n))=0

We add all the numbers together, and all the variables

4n+2n-(-7(n+2)-(-3n+6))=0

We add all the numbers together, and all the variables

6n-(-7(n+2)-(-3n+6))=0



We calculate terms in parentheses: -(-7(n+2)-(-3n+6)), so:

-7(n+2)-(-3n+6)

We multiply parentheses

-7n-(-3n+6)-14

We get rid of parentheses

-7n+3n-6-14

We add all the numbers together, and all the variables

-4n-20

Back to the equation:

-(-4n-20)



We get rid of parentheses

6n+4n+20=0

We add all the numbers together, and all the variables

10n+20=0

We move all terms containing n to the left, all other terms to the right

10n=-20

n=-20/10

n=-2

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