9-5(4-3)=-16+c

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Solution for 9-5(4-3)=-16+c equation: 



9-5(4-3)=-16+c

We move all terms to the left:

9-5(4-3)-(-16+c)=0

We add all the numbers together, and all the variables

-(c-16)+9-51=0

We add all the numbers together, and all the variables

-(c-16)-42=0

We get rid of parentheses

-c+16-42=0

We add all the numbers together, and all the variables

-1c-26=0

We move all terms containing c to the left, all other terms to the right

-c=26

c=26/-1

c=-26

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