9-2*(x-2)=4x-2*(x-5)-3

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Solution for 9-2*(x-2)=4x-2*(x-5)-3 equation: 



9-2(x-2)=4x-2(x-5)-3

We move all terms to the left:

9-2(x-2)-(4x-2(x-5)-3)=0

We multiply parentheses

-2x-(4x-2(x-5)-3)+4+9=0



We calculate terms in parentheses: -(4x-2(x-5)-3), so:

4x-2(x-5)-3

We multiply parentheses

4x-2x+10-3

We add all the numbers together, and all the variables

2x+7

Back to the equation:

-(2x+7)



We add all the numbers together, and all the variables

-2x-(2x+7)+13=0

We get rid of parentheses

-2x-2x-7+13=0

We add all the numbers together, and all the variables

-4x+6=0

We move all terms containing x to the left, all other terms to the right

-4x=-6

x=-6/-4

x=1+1/2

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