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(9x+1)(3x+7)=0
We multiply parentheses ..
(+27x^2+63x+3x+7)=0
We get rid of parentheses
27x^2+63x+3x+7=0
We add all the numbers together, and all the variables
27x^2+66x+7=0
a = 27; b = 66; c = +7;
Δ = b2-4ac
Δ = 662-4·27·7
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-60}{2*27}=\frac{-126}{54} =-2+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+60}{2*27}=\frac{-6}{54} =-1/9 $
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