20=2(3x+2)+2(x+4)

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Solution for 20=2(3x+2)+2(x+4) equation: 



20=2(3x+2)+2(x+4)

We move all terms to the left:

20-(2(3x+2)+2(x+4))=0



We calculate terms in parentheses: -(2(3x+2)+2(x+4)), so:

2(3x+2)+2(x+4)

We multiply parentheses

6x+2x+4+8

We add all the numbers together, and all the variables

8x+12

Back to the equation:

-(8x+12)



We get rid of parentheses

-8x-12+20=0

We add all the numbers together, and all the variables

-8x+8=0

We move all terms containing x to the left, all other terms to the right

-8x=-8

x=-8/-8

x=1

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