9-(1)/(2)n=5+4n

Solution for 9-(1)/(2)n=5+4n equation:

9-(1)/(2)n=5+4n

We move all terms to the left:

9-(1)/(2)n-(5+4n)=0


Domain of the equation: 2n!=0

n!=0/2

n!=0

n∈R


We add all the numbers together, and all the variables

-1/2n-(4n+5)+9=0

We get rid of parentheses

-1/2n-4n-5+9=0

We multiply all the terms by the denominator


-4n*2n-5*2n+9*2n-1=0

Wy multiply elements

-8n^2-10n+18n-1=0

We add all the numbers together, and all the variables

-8n^2+8n-1=0

a = -8; b = 8; c = -1;
Δ = b2-4ac
Δ = 82-4·(-8)·(-1)
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{2}}{2*-8}=\frac{-8-4\sqrt{2}}{-16}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{2}}{2*-8}=\frac{-8+4\sqrt{2}}{-16}
$