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4/5x-3=2/11x-7
We move all terms to the left:
4/5x-3-(2/11x-7)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 11x-7)!=0We get rid of parentheses
x∈R
4/5x-2/11x+7-3=0
We calculate fractions
44x/55x^2+(-10x)/55x^2+7-3=0
We add all the numbers together, and all the variables
44x/55x^2+(-10x)/55x^2+4=0
We multiply all the terms by the denominator
44x+(-10x)+4*55x^2=0
Wy multiply elements
220x^2+44x+(-10x)=0
We get rid of parentheses
220x^2+44x-10x=0
We add all the numbers together, and all the variables
220x^2+34x=0
a = 220; b = 34; c = 0;
Δ = b2-4ac
Δ = 342-4·220·0
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-34}{2*220}=\frac{-68}{440} =-17/110 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+34}{2*220}=\frac{0}{440} =0 $
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