8-(2)/(9)b=(1)/(3)b-7

Solution for 8-(2)/(9)b=(1)/(3)b-7 equation:

8-(2)/(9)b=(1)/(3)b-7

We move all terms to the left:

8-(2)/(9)b-((1)/(3)b-7)=0


Domain of the equation: 9b!=0

b!=0/9

b!=0

b∈R



Domain of the equation: 3b-7)!=0

b∈R


We get rid of parentheses

-2/9b-1/3b+7+8=0

We calculate fractions


(-6b)/27b^2+(-9b)/27b^2+7+8=0

We add all the numbers together, and all the variables

(-6b)/27b^2+(-9b)/27b^2+15=0

We multiply all the terms by the denominator


(-6b)+(-9b)+15*27b^2=0

Wy multiply elements

405b^2+(-6b)+(-9b)=0

We get rid of parentheses

405b^2-6b-9b=0

We add all the numbers together, and all the variables

405b^2-15b=0

a = 405; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·405·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*405}=\frac{0}{810}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*405}=\frac{30}{810}
=1/27
$