9(x-5)/12=3(x+2)/8

Solution for 9(x-5)/12=3(x+2)/8 equation:

9(x-5)/12=3(x+2)/8

We move all terms to the left:

9(x-5)/12-(3(x+2)/8)=0

We calculate fractions


9x/()+(-(3(x+2)*12)/()=0


We calculate terms in parentheses: +(-(3(x+2)*12)/(), so:

-(3(x+2)*12)/(

We multiply all the terms by the denominator


-(3(x+2)*12)


We calculate terms in parentheses: -(3(x+2)*12), so:

3(x+2)*12

We multiply parentheses

36x+72

Back to the equation:

-(36x+72)


We get rid of parentheses

-36x-72

Back to the equation:

+(-36x-72)


We get rid of parentheses

9x/()-36x-72=0

We multiply all the terms by the denominator


9x-36x*()-72*()=0

We add all the numbers together, and all the variables

9x-36x*()=0