-(3x-2)-(6x-4)+2=-8(x-2)-(4x+4)+5

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Solution for -(3x-2)-(6x-4)+2=-8(x-2)-(4x+4)+5 equation: 



-(3x-2)-(6x-4)+2=-8(x-2)-(4x+4)+5

We move all terms to the left:

-(3x-2)-(6x-4)+2-(-8(x-2)-(4x+4)+5)=0

We get rid of parentheses

-3x-6x-(-8(x-2)-(4x+4)+5)+2+4+2=0



We calculate terms in parentheses: -(-8(x-2)-(4x+4)+5), so:

-8(x-2)-(4x+4)+5

We multiply parentheses

-8x-(4x+4)+16+5

We get rid of parentheses

-8x-4x-4+16+5

We add all the numbers together, and all the variables

-12x+17

Back to the equation:

-(-12x+17)



We add all the numbers together, and all the variables

-9x-(-12x+17)+8=0

We get rid of parentheses

-9x+12x-17+8=0

We add all the numbers together, and all the variables

3x-9=0

We move all terms containing x to the left, all other terms to the right

3x=9

x=9/3

x=3

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