-(3x-8)-(4x-8)+7=-7(x-5)-(2x+2)+3

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Solution for -(3x-8)-(4x-8)+7=-7(x-5)-(2x+2)+3 equation: 



-(3x-8)-(4x-8)+7=-7(x-5)-(2x+2)+3

We move all terms to the left:

-(3x-8)-(4x-8)+7-(-7(x-5)-(2x+2)+3)=0

We get rid of parentheses

-3x-4x-(-7(x-5)-(2x+2)+3)+8+8+7=0



We calculate terms in parentheses: -(-7(x-5)-(2x+2)+3), so:

-7(x-5)-(2x+2)+3

We multiply parentheses

-7x-(2x+2)+35+3

We get rid of parentheses

-7x-2x-2+35+3

We add all the numbers together, and all the variables

-9x+36

Back to the equation:

-(-9x+36)



We add all the numbers together, and all the variables

-7x-(-9x+36)+23=0

We get rid of parentheses

-7x+9x-36+23=0

We add all the numbers together, and all the variables

2x-13=0

We move all terms containing x to the left, all other terms to the right

2x=13

x=13/2

x=6+1/2

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