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9(x+3)=4(x-7)+5
We move all terms to the left:
9(x+3)-(4(x-7)+5)=0
We multiply parentheses
9x-(4(x-7)+5)+27=0
We calculate terms in parentheses: -(4(x-7)+5), so:We get rid of parentheses
4(x-7)+5
We multiply parentheses
4x-28+5
We add all the numbers together, and all the variables
4x-23
Back to the equation:
-(4x-23)
9x-4x+23+27=0
We add all the numbers together, and all the variables
5x+50=0
We move all terms containing x to the left, all other terms to the right
5x=-50
x=-50/5
x=-10
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