3v+3(2v-6)=11v+12

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Solution for 3v+3(2v-6)=11v+12 equation: 



3v+3(2v-6)=11v+12

We move all terms to the left:

3v+3(2v-6)-(11v+12)=0

We multiply parentheses

3v+6v-(11v+12)-18=0

We get rid of parentheses

3v+6v-11v-12-18=0

We add all the numbers together, and all the variables

-2v-30=0

We move all terms containing v to the left, all other terms to the right

-2v=30

v=30/-2

v=-15

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