2(3u+7)=4-(3-2u)

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Solution for 2(3u+7)=4-(3-2u) equation: 



2(3u+7)=4-(3-2u)

We move all terms to the left:

2(3u+7)-(4-(3-2u))=0

We add all the numbers together, and all the variables

2(3u+7)-(4-(-2u+3))=0

We multiply parentheses

6u-(4-(-2u+3))+14=0



We calculate terms in parentheses: -(4-(-2u+3)), so:

4-(-2u+3)

determiningTheFunctionDomain
-(-2u+3)+4

We get rid of parentheses

2u-3+4

We add all the numbers together, and all the variables

2u+1

Back to the equation:

-(2u+1)



We get rid of parentheses

6u-2u-1+14=0

We add all the numbers together, and all the variables

4u+13=0

We move all terms containing u to the left, all other terms to the right

4u=-13

u=-13/4

u=-3+1/4

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