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3(2x-5)=6(x+1)
We move all terms to the left:
3(2x-5)-(6(x+1))=0
We multiply parentheses
6x-(6(x+1))-15=0
We calculate terms in parentheses: -(6(x+1)), so:We get rid of parentheses
6(x+1)
We multiply parentheses
6x+6
Back to the equation:
-(6x+6)
6x-6x-6-15=0
We add all the numbers together, and all the variables
-21!=0
There is no solution for this equation
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