9(n+3)-9(n+8)=6(n-11)-7(n-3

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Solution for 9(n+3)-9(n+8)=6(n-11)-7(n-3 equation: 



9(n+3)-9(n+8)=6(n-11)-7(n-3

We move all terms to the left:

9(n+3)-9(n+8)-(6(n-11)-7(n-3)=0

We multiply parentheses

9n-9n-(6(n-11)-7(n-3)+27-72=0

We add all the numbers together, and all the variables

-(6(n-11)-7(n-3)+27-72=0

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