4d2-13d-12=0

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Solution for 4d2-13d-12=0 equation:



4d^2-13d-12=0
a = 4; b = -13; c = -12;
Δ = b2-4ac
Δ = -132-4·4·(-12)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-19}{2*4}=\frac{-6}{8} =-3/4 $
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+19}{2*4}=\frac{32}{8} =4 $

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