6=3(b-4)

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Solution for 6=3(b-4) equation: 



6=3(b-4)

We move all terms to the left:

6-(3(b-4))=0



We calculate terms in parentheses: -(3(b-4)), so:

3(b-4)

We multiply parentheses

3b-12

Back to the equation:

-(3b-12)



We get rid of parentheses

-3b+12+6=0

We add all the numbers together, and all the variables

-3b+18=0

We move all terms containing b to the left, all other terms to the right

-3b=-18

b=-18/-3

b=+6

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