9(11-k)=3(33k-9)

Solution for 9(11-k)=3(33k-9) equation:

9(11-k)=3(33k-9)

We move all terms to the left:

9(11-k)-(3(33k-9))=0

We add all the numbers together, and all the variables

9(-1k+11)-(3(33k-9))=0

We multiply parentheses

-9k-(3(33k-9))+99=0


We calculate terms in parentheses: -(3(33k-9)), so:

3(33k-9)

We multiply parentheses

99k-27

Back to the equation:

-(99k-27)


We get rid of parentheses

-9k-99k+27+99=0

We add all the numbers together, and all the variables

-108k+126=0

We move all terms containing k to the left, all other terms to the right

-108k=-126

k=-126/-108

k=1+1/6