6+4(3x-5)=8-5(2x+1)

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Solution for 6+4(3x-5)=8-5(2x+1) equation: 



6+4(3x-5)=8-5(2x+1)

We move all terms to the left:

6+4(3x-5)-(8-5(2x+1))=0

We multiply parentheses

12x-(8-5(2x+1))-20+6=0



We calculate terms in parentheses: -(8-5(2x+1)), so:

8-5(2x+1)

determiningTheFunctionDomain
-5(2x+1)+8

We multiply parentheses

-10x-5+8

We add all the numbers together, and all the variables

-10x+3

Back to the equation:

-(-10x+3)



We add all the numbers together, and all the variables

12x-(-10x+3)-14=0

We get rid of parentheses

12x+10x-3-14=0

We add all the numbers together, and all the variables

22x-17=0

We move all terms containing x to the left, all other terms to the right

22x=17

x=17/22

x=17/22

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