8y-4=-4-(1/2y)

Solution for 8y-4=-4-(1/2y) equation:

8y-4=-4-(1/2y)

We move all terms to the left:

8y-4-(-4-(1/2y))=0


Domain of the equation: 2y))!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

8y-(-4-(+1/2y))-4=0

We multiply all the terms by the denominator


8y*2y))-(-4-(-4*2y))+1=0

Wy multiply elements

16y^2-8y=0

a = 16; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·16·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*16}=\frac{0}{32}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*16}=\frac{16}{32}
=1/2
$