2(96+x)=3(80-x)

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Solution for 2(96+x)=3(80-x) equation: 



2(96+x)=3(80-x)

We move all terms to the left:

2(96+x)-(3(80-x))=0

We add all the numbers together, and all the variables

2(x+96)-(3(-1x+80))=0

We multiply parentheses

2x-(3(-1x+80))+192=0



We calculate terms in parentheses: -(3(-1x+80)), so:

3(-1x+80)

We multiply parentheses

-3x+240

Back to the equation:

-(-3x+240)



We get rid of parentheses

2x+3x-240+192=0

We add all the numbers together, and all the variables

5x-48=0

We move all terms containing x to the left, all other terms to the right

5x=48

x=48/5

x=9+3/5

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