N=6,n2=36

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Solution for N=6,n2=36 equation: 



=6.N^2=36

We move all terms to the left:

-(6.N^2)=0

We get rid of parentheses

-6.N^2=0

We add all the numbers together, and all the variables

-6N^2=0

a = -6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$N=\frac{-b}{2a}=\frac{0}{-12}=0$

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