8y-4+2(3y+4)=-2(y+3)

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Solution for 8y-4+2(3y+4)=-2(y+3) equation: 



8y-4+2(3y+4)=-2(y+3)

We move all terms to the left:

8y-4+2(3y+4)-(-2(y+3))=0

We multiply parentheses

8y+6y-(-2(y+3))+8-4=0



We calculate terms in parentheses: -(-2(y+3)), so:

-2(y+3)

We multiply parentheses

-2y-6

Back to the equation:

-(-2y-6)



We add all the numbers together, and all the variables

14y-(-2y-6)+4=0

We get rid of parentheses

14y+2y+6+4=0

We add all the numbers together, and all the variables

16y+10=0

We move all terms containing y to the left, all other terms to the right

16y=-10

y=-10/16

y=-5/8

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