(2/3)x+3/8=(3/4)x-4

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Solution for (2/3)x+3/8=(3/4)x-4 equation: 



(2/3)x+3/8=(3/4)x-4

We move all terms to the left:

(2/3)x+3/8-((3/4)x-4)=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 4)x-4)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/3)x-((+3/4)x-4)+3/8=0

We multiply parentheses

2x^2-((+3/4)x-4)+3/8=0

We calculate fractions


2x^2+()/4x-4)*8)+12x/4x-4)*8)=0

We calculate fractions


2x^2+(()*4x)/16x^2+(-4)*8)+12x*4x)/16x^2=0

We multiply all the terms by the denominator


2x^2*16x^2+(()*4x)+(-4)*8)+12x*4x)=0



We calculate terms in parentheses: +(()*4x), so:

()*4x



Wy multiply elements

32x^4+(()*4x)+(-4)*8)+12x*4x)=0

We get rid of parentheses

32x^4+(()*4x)-4)*8)+12x*4x=0



We calculate terms in parentheses: +(()*4x), so:

()*4x



We do not support expression: x^4

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