(b/11)-(3b/11)=16/11

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Solution for (b/11)-(3b/11)=16/11 equation: 



(b/11)-(3b/11)=16/11

We move all terms to the left:

(b/11)-(3b/11)-(16/11)=0

We add all the numbers together, and all the variables

(+b/11)-(+3b/11)-(+16/11)=0

We get rid of parentheses

b/11-3b/11-16/11=0

We multiply all the terms by the denominator


b-3b-16=0

We add all the numbers together, and all the variables

-2b-16=0

We move all terms containing b to the left, all other terms to the right

-2b=16

b=16/-2

b=-8

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