8y-(4y+19)=3-(3y-4)

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Solution for 8y-(4y+19)=3-(3y-4) equation: 



8y-(4y+19)=3-(3y-4)

We move all terms to the left:

8y-(4y+19)-(3-(3y-4))=0

We get rid of parentheses

8y-4y-(3-(3y-4))-19=0



We calculate terms in parentheses: -(3-(3y-4)), so:

3-(3y-4)

determiningTheFunctionDomain
-(3y-4)+3

We get rid of parentheses

-3y+4+3

We add all the numbers together, and all the variables

-3y+7

Back to the equation:

-(-3y+7)



We add all the numbers together, and all the variables

4y-(-3y+7)-19=0

We get rid of parentheses

4y+3y-7-19=0

We add all the numbers together, and all the variables

7y-26=0

We move all terms containing y to the left, all other terms to the right

7y=26

y=26/7

y=3+5/7

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