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-2=2x^2-3x+8
We move all terms to the left:
-2-(2x^2-3x+8)=0
We get rid of parentheses
-2x^2+3x-8-2=0
We add all the numbers together, and all the variables
-2x^2+3x-10=0
a = -2; b = 3; c = -10;
Δ = b2-4ac
Δ = 32-4·(-2)·(-10)
Δ = -71
Delta is less than zero, so there is no solution for the equation
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