4(x-2)=-(3x-5)+3

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Solution for 4(x-2)=-(3x-5)+3 equation: 



4(x-2)=-(3x-5)+3

We move all terms to the left:

4(x-2)-(-(3x-5)+3)=0

We multiply parentheses

4x-(-(3x-5)+3)-8=0



We calculate terms in parentheses: -(-(3x-5)+3), so:

-(3x-5)+3

We get rid of parentheses

-3x+5+3

We add all the numbers together, and all the variables

-3x+8

Back to the equation:

-(-3x+8)



We get rid of parentheses

4x+3x-8-8=0

We add all the numbers together, and all the variables

7x-16=0

We move all terms containing x to the left, all other terms to the right

7x=16

x=16/7

x=2+2/7

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