8y+3(y-7)=5(y+1)-4

Solution for 8y+3(y-7)=5(y+1)-4 equation:

8y+3(y-7)=5(y+1)-4

We move all terms to the left:

8y+3(y-7)-(5(y+1)-4)=0

We multiply parentheses

8y+3y-(5(y+1)-4)-21=0


We calculate terms in parentheses: -(5(y+1)-4), so:

5(y+1)-4

We multiply parentheses

5y+5-4

We add all the numbers together, and all the variables

5y+1

Back to the equation:

-(5y+1)


We add all the numbers together, and all the variables

11y-(5y+1)-21=0

We get rid of parentheses

11y-5y-1-21=0

We add all the numbers together, and all the variables

6y-22=0

We move all terms containing y to the left, all other terms to the right

6y=22

y=22/6

y=3+2/3