1+3(x+4)=4(x-2)

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Solution for 1+3(x+4)=4(x-2) equation: 



1+3(x+4)=4(x-2)

We move all terms to the left:

1+3(x+4)-(4(x-2))=0

We multiply parentheses

3x-(4(x-2))+12+1=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We add all the numbers together, and all the variables

3x-(4x-8)+13=0

We get rid of parentheses

3x-4x+8+13=0

We add all the numbers together, and all the variables

-1x+21=0

We move all terms containing x to the left, all other terms to the right

-x=-21

x=-21/-1

x=+21

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