-9(t+6)+3(4t+8)=2(t-5)-9

Solution for -9(t+6)+3(4t+8)=2(t-5)-9 equation:

-9(t+6)+3(4t+8)=2(t-5)-9

We move all terms to the left:

-9(t+6)+3(4t+8)-(2(t-5)-9)=0

We multiply parentheses

-9t+12t-(2(t-5)-9)-54+24=0


We calculate terms in parentheses: -(2(t-5)-9), so:

2(t-5)-9

We multiply parentheses

2t-10-9

We add all the numbers together, and all the variables

2t-19

Back to the equation:

-(2t-19)


We add all the numbers together, and all the variables

3t-(2t-19)-30=0

We get rid of parentheses

3t-2t+19-30=0

We add all the numbers together, and all the variables

t-11=0

We move all terms containing t to the left, all other terms to the right

t=11