8x-4/3x=3

Solution for 8x-4/3x=3 equation:

8x-4/3x=3

We move all terms to the left:

8x-4/3x-(3)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We multiply all the terms by the denominator


8x*3x-3*3x-4=0

Wy multiply elements

24x^2-9x-4=0

a = 24; b = -9; c = -4;
Δ = b2-4ac
Δ = -92-4·24·(-4)
Δ = 465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{465}}{2*24}=\frac{9-\sqrt{465}}{48}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{465}}{2*24}=\frac{9+\sqrt{465}}{48}
$