192=(5x+2)x

Solution for 192=(5x+2)x equation:

192=(5x+2)x

We move all terms to the left:

192-((5x+2)x)=0


We calculate terms in parentheses: -((5x+2)x), so:

(5x+2)x

We multiply parentheses

5x^2+2x

Back to the equation:

-(5x^2+2x)


We get rid of parentheses

-5x^2-2x+192=0

a = -5; b = -2; c = +192;
Δ = b2-4ac
Δ = -22-4·(-5)·192
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-62}{2*-5}=\frac{-60}{-10}
=+6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+62}{2*-5}=\frac{64}{-10}
=-6+2/5
$