8x+3=8x(1-x)

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Solution for 8x+3=8x(1-x) equation: 



8x+3=8x(1-x)

We move all terms to the left:

8x+3-(8x(1-x))=0

We add all the numbers together, and all the variables

8x-(8x(-1x+1))+3=0



We calculate terms in parentheses: -(8x(-1x+1)), so:

8x(-1x+1)

We multiply parentheses

-8x^2+8x

Back to the equation:

-(-8x^2+8x)



We get rid of parentheses

8x^2-8x+8x+3=0

We add all the numbers together, and all the variables

8x^2+3=0

a = 8; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·8·3
Δ = -96
Delta is less than zero, so there is no solution for the equation

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