X2+140=4x+19

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Solution for X2+140=4x+19 equation: 



X2+140=4X+19

We move all terms to the left:

X2+140-(4X+19)=0

We add all the numbers together, and all the variables

X^2-(4X+19)+140=0

We get rid of parentheses

X^2-4X-19+140=0

We add all the numbers together, and all the variables

X^2-4X+121=0

a = 1; b = -4; c = +121;
Δ = b2-4ac
Δ = -42-4·1·121
Δ = -468
Delta is less than zero, so there is no solution for the equation

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