1/3x+9=2(22-x)

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Solution for 1/3x+9=2(22-x) equation: 



1/3x+9=2(22-x)

We move all terms to the left:

1/3x+9-(2(22-x))=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



We add all the numbers together, and all the variables

1/3x-(2(-1x+22))+9=0

We multiply all the terms by the denominator


-((2(-1x+22)))*3x+9*3x+1=0

Wy multiply elements

-((2(-1x+22)))*3x+27x+1=0

We add all the numbers together, and all the variables

27x-((2(-1x+22)))*3x+1=0

We move all terms containing x to the left, all other terms to the right

27x-((2(-1x+22)))*3x=-1

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