8x+20+4x=5(2x-1)+9

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Solution for 8x+20+4x=5(2x-1)+9 equation: 



8x+20+4x=5(2x-1)+9

We move all terms to the left:

8x+20+4x-(5(2x-1)+9)=0

We add all the numbers together, and all the variables

12x-(5(2x-1)+9)+20=0



We calculate terms in parentheses: -(5(2x-1)+9), so:

5(2x-1)+9

We multiply parentheses

10x-5+9

We add all the numbers together, and all the variables

10x+4

Back to the equation:

-(10x+4)



We get rid of parentheses

12x-10x-4+20=0

We add all the numbers together, and all the variables

2x+16=0

We move all terms containing x to the left, all other terms to the right

2x=-16

x=-16/2

x=-8

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