6(y+3)=3(y-10)

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Solution for 6(y+3)=3(y-10) equation: 



6(y+3)=3(y-10)

We move all terms to the left:

6(y+3)-(3(y-10))=0

We multiply parentheses

6y-(3(y-10))+18=0



We calculate terms in parentheses: -(3(y-10)), so:

3(y-10)

We multiply parentheses

3y-30

Back to the equation:

-(3y-30)



We get rid of parentheses

6y-3y+30+18=0

We add all the numbers together, and all the variables

3y+48=0

We move all terms containing y to the left, all other terms to the right

3y=-48

y=-48/3

y=-16

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