X+3x+(4x-5)=99

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Solution for X+3x+(4x-5)=99 equation: 



X+3X+(4X-5)=99

We move all terms to the left:

X+3X+(4X-5)-(99)=0

We add all the numbers together, and all the variables

4X+(4X-5)-99=0

We get rid of parentheses

4X+4X-5-99=0

We add all the numbers together, and all the variables

8X-104=0

We move all terms containing X to the left, all other terms to the right

8X=104

X=104/8

X=13

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