8x+2(4x-3)=4(6x+4)-6

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Solution for 8x+2(4x-3)=4(6x+4)-6 equation: 



8x+2(4x-3)=4(6x+4)-6

We move all terms to the left:

8x+2(4x-3)-(4(6x+4)-6)=0

We multiply parentheses

8x+8x-(4(6x+4)-6)-6=0



We calculate terms in parentheses: -(4(6x+4)-6), so:

4(6x+4)-6

We multiply parentheses

24x+16-6

We add all the numbers together, and all the variables

24x+10

Back to the equation:

-(24x+10)



We add all the numbers together, and all the variables

16x-(24x+10)-6=0

We get rid of parentheses

16x-24x-10-6=0

We add all the numbers together, and all the variables

-8x-16=0

We move all terms containing x to the left, all other terms to the right

-8x=16

x=16/-8

x=-2

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