(X+4)/9=(x+2)/3

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Solution for (X+4)/9=(x+2)/3 equation: 



(X+4)/9=(X+2)/3

We move all terms to the left:

(X+4)/9-((X+2)/3)=0

We calculate fractions


X/()+(-((X+2)*9)/()=0



We calculate terms in parentheses: +(-((X+2)*9)/(), so:

-((X+2)*9)/(

We multiply all the terms by the denominator


-((X+2)*9)



We calculate terms in parentheses: -((X+2)*9), so:

(X+2)*9

We multiply parentheses

9X+18

Back to the equation:

-(9X+18)



We get rid of parentheses

-9X-18

Back to the equation:

+(-9X-18)



We get rid of parentheses

X/()-9X-18=0

We multiply all the terms by the denominator


X-9X*()-18*()=0

We add all the numbers together, and all the variables

X-9X*()=0

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