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8x(x-6)=34
We move all terms to the left:
8x(x-6)-(34)=0
We multiply parentheses
8x^2-48x-34=0
a = 8; b = -48; c = -34;
Δ = b2-4ac
Δ = -482-4·8·(-34)
Δ = 3392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3392}=\sqrt{64*53}=\sqrt{64}*\sqrt{53}=8\sqrt{53}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-8\sqrt{53}}{2*8}=\frac{48-8\sqrt{53}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+8\sqrt{53}}{2*8}=\frac{48+8\sqrt{53}}{16} $
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