8v+2-2(-4v-4)=4(v-1)

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Solution for 8v+2-2(-4v-4)=4(v-1) equation: 



8v+2-2(-4v-4)=4(v-1)

We move all terms to the left:

8v+2-2(-4v-4)-(4(v-1))=0

We multiply parentheses

8v+8v-(4(v-1))+8+2=0



We calculate terms in parentheses: -(4(v-1)), so:

4(v-1)

We multiply parentheses

4v-4

Back to the equation:

-(4v-4)



We add all the numbers together, and all the variables

16v-(4v-4)+10=0

We get rid of parentheses

16v-4v+4+10=0

We add all the numbers together, and all the variables

12v+14=0

We move all terms containing v to the left, all other terms to the right

12v=-14

v=-14/12

v=-1+1/6

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