(8/9)*(3i+27)=(2/9)i+68

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Solution for (8/9)*(3i+27)=(2/9)i+68 equation: 



(8/9)(3i+27)=(2/9)i+68

We move all terms to the left:

(8/9)(3i+27)-((2/9)i+68)=0



Domain of the equation: 9)(3i+27)!=0

i∈R





Domain of the equation: 9)i+68)!=0

i!=0/1

i!=0

i∈R



We add all the numbers together, and all the variables

(+8/9)(3i+27)-((+2/9)i+68)=0

We multiply parentheses ..

(+24i^2+8/9*27)-((+2/9)i+68)=0

We calculate fractions

We do not support eipression: i^3

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