8c-42=1/3(6-9c

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Solution for 8c-42=1/3(6-9c equation: 



8c-42=1/3(6-9c

We move all terms to the left:

8c-42-(1/3(6-9c)=0



Domain of the equation: 3(6-9c)-42!=0

We move all terms containing c to the left, all other terms to the right

3(6-9c)!=42

c∈R



We add all the numbers together, and all the variables

8c-(1/3(-9c+6)-42=0

We multiply all the terms by the denominator


8c*3(-9c+6)-42-(1=0

We add all the numbers together, and all the variables

8c*3(-9c+6)=0

Wy multiply elements

24c^2(-=0

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