(2x-10)(3x+15)=0

Solution for (2x-10)(3x+15)=0 equation:

(2x-10)(3x+15)=0

We multiply parentheses ..

(+6x^2+30x-30x-150)=0

We get rid of parentheses

6x^2+30x-30x-150=0

We add all the numbers together, and all the variables

6x^2-150=0

a = 6; b = 0; c = -150;
Δ = b2-4ac
Δ = 02-4·6·(-150)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*6}=\frac{-60}{12}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*6}=\frac{60}{12}
=5
$