8a-(5a+10=-2(a-3))

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Solution for 8a-(5a+10=-2(a-3)) equation: 



8a-(5a+10=-2(a-3))

We move all terms to the left:

8a-(5a+10-(-2(a-3)))=0



We calculate terms in parentheses: -(5a+10-(-2(a-3))), so:

5a+10-(-2(a-3))

determiningTheFunctionDomain
5a-(-2(a-3))+10



We calculate terms in parentheses: -(-2(a-3)), so:

-2(a-3)

We multiply parentheses

-2a+6

Back to the equation:

-(-2a+6)



We get rid of parentheses

5a+2a-6+10

We add all the numbers together, and all the variables

7a+4

Back to the equation:

-(7a+4)



We get rid of parentheses

8a-7a-4=0

We add all the numbers together, and all the variables

a-4=0

We move all terms containing a to the left, all other terms to the right

a=4

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